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  1. WildFly Core
  2. WFCORE-1596

Echo commands without arguments doesn't print existing variables - update help message

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    • Icon: Bug Bug
    • Resolution: Done
    • Icon: Major Major
    • 3.0.0.Alpha2
    • 3.0.0.Alpha1
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      According to the help message:

         If the command is executed w/o arguments then the command will print
   all the existing variables with their values in the name=value format.

      actual

      [standalone@localhost:9990 /] set foo=bar
[standalone@localhost:9990 /] echo $foo
bar
[standalone@localhost:9990 /] echo

[standalone@localhost:9990 /]

      expected

      [standalone@localhost:9990 /] set foo=bar
[standalone@localhost:9990 /] echo $foo
bar
[standalone@localhost:9990 /] echo
foo=bar
[standalone@localhost:9990 /]

              olubyans@redhat.com Alexey Loubyansky
              olubyans@redhat.com Alexey Loubyansky
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                Created:
                Updated:
                Resolved: