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  1. Infinispan
  2. ISPN-1801

Virtual nodes should be enabled by default

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Details

    • Feature Request
    • Status: Closed (View Workflow)
    • Major
    • Resolution: Done
    • 5.1.0.FINAL
    • 5.1.1.CR1, 5.1.1.FINAL
    • Core
    • None

    Description

      ATM the default value for virtualNodes is 1. This means that the wheel-share each node has can be very uneven for small(up to 15 nodes) clusters.
      Increasing this value even to a small number(10-30) would significantly improve each node's share of wheel and the chance for a well balanced data distribution over the cluster.

      Here are some suggestions from an email from Dan:
      <snip>

      I've been working on a test to search for an optimal default value here:
      https://github.com/danberindei/infinispan/commit/983c0328dc40be9609fcabb767dd46f9b98af464

      I'm measuring both the number of keys for which a node is primary
      owner and the number of keys for which it is one of the owners
      compared to the ideal distribution (K/N keys on each node). The former
      tells us how much more work the node could be expected to do, the
      latter how much memory the node is likely to need.

      I'm only running 10000 loops, so the max figure is not the absolute
      maximum. But it's certainly bigger than the 0.9999 percentile.

      The full results are here:
      https://github.com/infinispan/infinispan/blob/master/core/src/test/java/org/infinispan/distribution/virtualnodes/vnodes_key_dist.txt

      The uniformity of the distribution goes up with the number of virtual
      nodes but down with the number of physical nodes. I think we should go
      with a default of 48 nodes (or 50 if you prefer decimal). With 32
      nodes, there's only a 0.1% chance that a node will hold more than 1.35

      • K/N keys, and a 0.1% chance that the node will be primary owner for
        more than 1.5 * K/N keys.

      We could go higher, but we run against the risk of node addresses
      colliding on the hash wheel. According to the formula on the Birthday
      Paradox page (http://en.wikipedia.org/wiki/Birthday_problem), we only
      need 2072 addresses on our 2^31 hash wheel to get a 0.1% chance of
      collision. That means 21 nodes * 96 virtual nodes, 32 nodes * 64
      virtual nodes or 43 nodes * 48 virtual nodes.

      </snip>

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            dberinde@redhat.com Dan Berindei
            mircea.markus Mircea Markus (Inactive)
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              Created:
              Updated:
              Resolved: